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<blockquote data-quote="eric" data-source="post: 204547" data-attributes="member: 7"><p>Sometime awhile back, one of you guys posted about how to figure the ratios needed to achieve what soil test results were. </p><p></p><p>In other words, if soil test shows you need 85 lbs/N per acre, what number would this equate to in real life. If you are putting down 28-8-6, how many lbs of each ingredient are you putting in 100 pounds of fertilizer?</p><p></p><p>My soil tests came back with </p><p></p><p>85 lbs of N/acre</p><p></p><p>55 lbs of P/acre</p><p></p><p>85 lbs of K/acre. </p><p></p><p>I realize that for a 10 acre pasture, I could just tell the dealer to mix me up 850 lbs N/550 lbs P/ 850 lbs of K, and then spread accordingly, but what would the proper analysis be?</p><p></p><p>85-55-85? I know that cant be right, so can I just start breaking it down from there....43-27-43 (1/2)......21-14-21 (1/4)? I know this is clear as mud, but hopefully someone can figure out what I am trying to ask!</p></blockquote><p></p>
[QUOTE="eric, post: 204547, member: 7"] Sometime awhile back, one of you guys posted about how to figure the ratios needed to achieve what soil test results were. In other words, if soil test shows you need 85 lbs/N per acre, what number would this equate to in real life. If you are putting down 28-8-6, how many lbs of each ingredient are you putting in 100 pounds of fertilizer? My soil tests came back with 85 lbs of N/acre 55 lbs of P/acre 85 lbs of K/acre. I realize that for a 10 acre pasture, I could just tell the dealer to mix me up 850 lbs N/550 lbs P/ 850 lbs of K, and then spread accordingly, but what would the proper analysis be? 85-55-85? I know that cant be right, so can I just start breaking it down from there....43-27-43 (1/2)......21-14-21 (1/4)? I know this is clear as mud, but hopefully someone can figure out what I am trying to ask! [/QUOTE]
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