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<blockquote data-quote="oakcreekfarms" data-source="post: 379019" data-attributes="member: 3177"><p>I am waiting for the wife to get home and was doing some more research on the topic, I found the equations that were being talked about earlier in the thread. </p><p>Basically it said to take (regrowth time/ stay time)+1= Paddocks needed</p><p></p><p>acres needed= (DM eaten x number of head x stay time)/ DM available per acre</p><p></p><p>I said that my regrowth might be 40 days and my stay would be 3, I listed my cows eating 40lbs per day of DM, I want to be able to run 50 cows, and I said that my DM available per acre was 1000.</p><p></p><p>(40/3)+1= 14.3</p><p>(40x50x3)/1000= 6 </p><p></p><p>I wouldn't start out at this, but does this math seem right. I am going to build into it, but would like to know what the possibilities are. My other question would be could your run 6 paddocks of 14.3 acres instead of 14.3 6 acres pastures. Wouldn't your stay time increase with paddock size?</p></blockquote><p></p>
[QUOTE="oakcreekfarms, post: 379019, member: 3177"] I am waiting for the wife to get home and was doing some more research on the topic, I found the equations that were being talked about earlier in the thread. Basically it said to take (regrowth time/ stay time)+1= Paddocks needed acres needed= (DM eaten x number of head x stay time)/ DM available per acre I said that my regrowth might be 40 days and my stay would be 3, I listed my cows eating 40lbs per day of DM, I want to be able to run 50 cows, and I said that my DM available per acre was 1000. (40/3)+1= 14.3 (40x50x3)/1000= 6 I wouldn't start out at this, but does this math seem right. I am going to build into it, but would like to know what the possibilities are. My other question would be could your run 6 paddocks of 14.3 acres instead of 14.3 6 acres pastures. Wouldn't your stay time increase with paddock size? [/QUOTE]
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