Menu
Forums
New posts
Search forums
What's new
New posts
New media
New media comments
New profile posts
Latest activity
Media
New media
New comments
Search media
Members
Current visitors
New profile posts
Search profile posts
Log in
Register
What's new
Search
Search
Search titles and first posts only
Search titles only
By:
New posts
Search forums
Menu
Log in
Register
Forums
Cattle Boards
Beginners Board
Had a round with a bull today.
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Reply to thread
Help Support CattleToday:
Message
<blockquote data-quote="greybeard" data-source="post: 1779310" data-attributes="member: 18945"><p>A hotshot...One on one, head to head on open ground with an aggressive bull?</p><p>No.</p><p>But lets think about what is actually going to happen..</p><p>IF, he's headed your way, you 'might' get one pulse into the bull before he runs you over. His moving mass is so great, he will barely feel it and for such a tiny amount of time, he won't even begin to slow down or turn away. Inertial mass. Momentum. What does that mean? If the cattle prod puts out 5000V that is theoretically 5000Joules of <u><strong>energy</strong></u>, but it's applied strictly between the 2 points on the end of the cattle prod (electrodes) usually about an inch apart from each other. </p><p></p><p>(why isn't an electrified fence that has 5000V advertised as 5000 joules of energy? Because the manufacturers have to take into account the length of the charged wire, the 'average point of contact' and the distance from an average point of contact back to the energizer and it's ground rod(s). (the shock doesn't actually take place until the pulse makes it back to the negative terminal within the energizer. This seems instantaneous to us, only because the electrons are traveling at near light speed)</p><p></p><p>But, back to the irritated bull that just got hit with 5000-5600 volt pulse from the hotshot.. We think of joules as an expression of electrical energy but it is also an expression of all other kinds of kinetic energy, and that hotshot pulse pales in comparison to the energy in that moving mass of angry bull and someone much smarter than I actually went to the trouble to calculate how much energy he is ready to unleash.</p><p></p><p>The formula for the kinetic energy of a non-rotating object is: Eᵏ=1/2mv².</p><p>Energy (joules) is equal to 1/2 of the mass of an object (in kilograms) multiplied by Velocity (speed) in meters per second squared. </p><p>If a bull weighs 1700 lbs, that gets converted to 771kilograms for mass.</p><p></p><p>It was determined, that the average bull runs at about 15mph which gets converted to 24 kilometers/hr but that has to be converted to meters/second. </p><p>Soooo, 24 Km changes to 24000 meters and divide that by 3600 (seconds) and you get 6.7.</p><p></p><p>plug all that in and you have:</p><p>Kinetic energy = .5 x 771 x 6.7² = 17,111 joules of raw mad energy coming at you and your measly little stick of electrons.</p></blockquote><p></p>
[QUOTE="greybeard, post: 1779310, member: 18945"] A hotshot...One on one, head to head on open ground with an aggressive bull? No. But lets think about what is actually going to happen.. IF, he's headed your way, you 'might' get one pulse into the bull before he runs you over. His moving mass is so great, he will barely feel it and for such a tiny amount of time, he won't even begin to slow down or turn away. Inertial mass. Momentum. What does that mean? If the cattle prod puts out 5000V that is theoretically 5000Joules of [U][B]energy[/B][/U], but it's applied strictly between the 2 points on the end of the cattle prod (electrodes) usually about an inch apart from each other. (why isn't an electrified fence that has 5000V advertised as 5000 joules of energy? Because the manufacturers have to take into account the length of the charged wire, the 'average point of contact' and the distance from an average point of contact back to the energizer and it's ground rod(s). (the shock doesn't actually take place until the pulse makes it back to the negative terminal within the energizer. This seems instantaneous to us, only because the electrons are traveling at near light speed) But, back to the irritated bull that just got hit with 5000-5600 volt pulse from the hotshot.. We think of joules as an expression of electrical energy but it is also an expression of all other kinds of kinetic energy, and that hotshot pulse pales in comparison to the energy in that moving mass of angry bull and someone much smarter than I actually went to the trouble to calculate how much energy he is ready to unleash. The formula for the kinetic energy of a non-rotating object is: Eᵏ=1/2mv². Energy (joules) is equal to 1/2 of the mass of an object (in kilograms) multiplied by Velocity (speed) in meters per second squared. If a bull weighs 1700 lbs, that gets converted to 771kilograms for mass. It was determined, that the average bull runs at about 15mph which gets converted to 24 kilometers/hr but that has to be converted to meters/second. Soooo, 24 Km changes to 24000 meters and divide that by 3600 (seconds) and you get 6.7. plug all that in and you have: Kinetic energy = .5 x 771 x 6.7² = 17,111 joules of raw mad energy coming at you and your measly little stick of electrons. [/QUOTE]
Insert quotes…
Verification
Post reply
Forums
Cattle Boards
Beginners Board
Had a round with a bull today.
Top