A. delaGarza":qa7le8w0 said:
very confuse
dun":qa7le8w0 said:
An animal that is heterozygous black, one black gene will be black. To be red, it must be homozygous red, two red genes, no black genes. But that doesn't address white or spotting
dun
at each loci, there are two genes. if both genes are the same, it is homozygous. if the genes are different, it is heterozygous.
black is dominant & we'll use "B" for black & "b" for non-black. if an animal is homozygous black, it has two black genes, BB. if an animal is heterozygous black, it has a black gene and a non-black gene, Bb. Both animals will be black in color but when crossed, the homozygous black animal (BB) can only pass on the black color gene (all his offspring will be black). The heterozygous black animal (Bb) can pass either the black gene or the non-black gene. Statistically, half the time he will pass on the black gene & half of the time, the non-black. If he is bred to homozygous black females (BB), all the offspring will still be black because the females are only passing on black color, but half of the offspring will carry the non-black gene (they will still appear black). If he is bred to heterozygous females, 1/4 of the offspring will be homozyous black, 1/2 will be heterozygous black (so 3/4 will appear black) & 1/4 will be homozygous non-black.
Spots & diluters are determined by genes at other loci & can affect the coloring.
Hope this helps clear up some confusion & didn't create more.